According to physics, why don't raindrops kill you?

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Raindrops do not kill people due to their relatively low mass and terminal velocity, which is insufficient to cause lethal impact. The discussion touches on the physics of raindrops, emphasizing that their size and speed limit their potential to inflict harm. Additionally, a humorous reference is made to the Violent Crime Control and Law Enforcement Act, suggesting that raindrops are not a threat. The conversation also critiques the NRA's stance on gun control in a satirical manner. Overall, the topic highlights the physics behind raindrop impacts and societal perceptions of violence.
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Please provide all relevant equations, laws, and background information if possible.
 
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annablax said:
Please provide all relevant equations, laws, and background information if possible.
Welcome to Physics Forums.

That's not the way it works here. We will help you with your homework, but we will not do it for you. You must put some effort in yourself.
 
Re: Why don't raindrops kill you

It is a well-known fact that the incidence of raindrop-related homicides has been steadily decreasing since Congress passed the Violent Crime Control and Law Enforcement Act (A.K.A Assault Weapons Ban) in 1994.

Provisions of this Act explicitly outlaw the sale of assault weapons to raindrops.

This act was opposed by the NRA which claimed that "if assault weapons are outlawed then only raindrops will have assault weapons". Obviously that argument is absurd, as are most of the NRA's arguments.
 
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Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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