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cold-peak
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[SOLVED] Accuracy & Error
Hi Everyone,
Just a quick question regarding Accuracy & Error.
We have been doing this for a little while (University) and I'm slightly confused with one of the problems.
I am able to do something like this and achieve the working and answer:
However, when presented with this, I am not sure how to approach it:
2. The attempt at a solution
I'm just not sure what to do to it... The answer is:
Just not sure how to get there, any help?EDIT: SOLVED - Was being silly!
Thanks
Hi Everyone,
Just a quick question regarding Accuracy & Error.
We have been doing this for a little while (University) and I'm slightly confused with one of the problems.
I am able to do something like this and achieve the working and answer:
Code:
(7.3 ± 0.4) x (1.2 ± 0.6) / (5.4 ± 1.3)
ie: 1.3 * 5.4 = 7.02
0.6/1.3 = 0.46
1.3/5.4 = 0.24
Square root of: 0.46^2 + 0.24^2 = 0.52
= 0.52 * 7.02 = 3.65 to take it out of fractional error form
= (7 ± 3.6) / (5.4 ± 1.3)
= 7/5.4 = 1.29
3.6/7 = 0.51
1.3/5.4 = 0.24
= square root of: 0.51^2 + 0.24^2 = 0.56
= 0.56 * 1.29= 0.7 (to take it out of fractional error form)
ans = (1.3 ± 0.7) * 10^4 etc
However, when presented with this, I am not sure how to approach it:
Homework Statement
Code:
(102 ± 32)^5
2. The attempt at a solution
I'm just not sure what to do to it... The answer is:
Code:
(1.1 ± 0.8) * 10^10
Thanks
Last edited: