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Homework Help: Accuracy & Error

  1. Nov 22, 2007 #1
    [SOLVED] Accuracy & Error

    Hi Everyone,

    Just a quick question regarding Accuracy & Error.

    We have been doing this for a little while (University) and I'm slightly confused with one of the problems.

    I am able to do something like this and achieve the working and answer:

    Code (Text):
    (7.3 ± 0.4) x (1.2 ± 0.6)    /     (5.4 ± 1.3)

    ie: 1.3 * 5.4 = 7.02

    0.6/1.3 = 0.46
    1.3/5.4 = 0.24

    Square root of: 0.46^2 + 0.24^2 = 0.52

    = 0.52 * 7.02 = 3.65 to take it out of fractional error form

    = (7 ± 3.6) / (5.4 ± 1.3)

    = 7/5.4 = 1.29

    3.6/7 = 0.51

    1.3/5.4 = 0.24

    = square root of: 0.51^2 + 0.24^2 = 0.56

    = 0.56 * 1.29= 0.7 (to take it out of fractional error form)

    ans = (1.3 ± 0.7) * 10^4 etc
     
    However, when presented with this, I am not sure how to approach it:

    1. The problem statement, all variables and given/known data
    Code (Text):
    (102 ± 32)^5
    2. The attempt at a solution
    I'm just not sure what to do to it... The answer is:
    Code (Text):
     (1.1 ± 0.8) * 10^10
    Just not sure how to get there, any help?


    EDIT: SOLVED - Was being silly!
    Thanks
     
    Last edited: Nov 22, 2007
  2. jcsd
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