Adding a dielectric to capacitors

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SUMMARY

The discussion focuses on the effects of inserting a dielectric slab into capacitor 2 while analyzing two identical capacitors. The potential difference across capacitor 1 remains unchanged when the dielectric is added. The charge on capacitor 2 decreases due to the reduced electric field caused by the dielectric. The capacitance of capacitor 1 also remains the same, while the potential energy stored in capacitor 2 decreases as the dielectric is introduced, confirming that adding a dielectric lowers the potential energy due to increased capacitance.

PREREQUISITES
  • Understanding of capacitor fundamentals, including capacitance and charge.
  • Knowledge of dielectric materials and their effects on electric fields.
  • Familiarity with energy storage in capacitors and the associated equations.
  • Basic circuit theory, particularly regarding parallel circuits and voltage relationships.
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  • Study the impact of different dielectric materials on capacitance and energy storage.
  • Learn about the mathematical relationship between capacitance, voltage, and stored energy in capacitors.
  • Explore the concept of electric fields in capacitors and how they change with dielectrics.
  • Investigate the behavior of capacitors in parallel circuits and their voltage characteristics.
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Homework Statement



Fig. 1 and 2 show a dielectric slab being inserted between the plates of one of two identical capacitors, capacitor 2. Select the correct answer to each of the statements below (enter I for `increases', D for `decreases', or S for `stays the same').

1. In Fig. 2, the potential difference between the plates of capacitor 1 _______ when the dielectric is inserted.
2. In Fig. 2, the charge on capacitor 2 _______ when the dielectric is inserted.
3. In Fig. 2, the capacitance of capacitor 1 _______ when the dielectric is inserted.
4. In Fig. 1, the potential energy stored in capacitor 2 _______ when the dielectric is inserted.

http://i.imagehost.org/view/0204/prob45

Homework Equations




The Attempt at a Solution



1. Stay the same - would it affect capacotor 1
2. stay the same, wouldn't the charge still be the sdame on the plates
3. stay the same - like 1
4. decrease - adding a dielectric decreases the potential, doesn't it
 
Last edited by a moderator:
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I agree that the first capacitor shouldn't change. Rethink your answers to the other two.
 
For 2, would the charge decrease because the electric field decreases (due to the dielectric).
and for 4,
would the potential increase, because the capitance would increase (C is proportional to K), and the energy is 0.5C(V)2
 
So from circuits you know that all the elements in parallel will always have the same voltage. Given that the voltage of the capacitor with the dielectric remains the same, what must happen to the charge?
 

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