Add Vectors: Angle & 3-Phase Systems

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To add two vectors with only the angle between them, additional information such as their magnitudes is essential. For example, with two vectors A and B at a 40-degree angle, the resultant cannot be determined without knowing their magnitudes. In three-phase systems, to find the resultant of two equal voltages with a 120-degree phase difference, the cosine rule can be applied, provided the magnitudes are known. An example calculation shows that two 100-volt voltages 120 degrees apart yield a resultant of 173 volts. Ultimately, both vector addition and three-phase voltage calculations require more than just the angle between the vectors.
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how to add two vectors knowing only angle between them for example if we have two vectors A and B having angle 40 degrees what will be the resultant sum of two?
also in three phase systems how to find resultant of two voltage of equal magnitude having a phase difference of 120 degrees
 
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You would need to know the magnitudes of the vectors.

Assuming you do know the magnitudes, you can either draw the vectors on graph paper and measure the resultant, or you can calculate it using the cosine rule:
http://en.wikipedia.org/wiki/Cosine_rule

For example, two 100 volt voltages are 120 degrees apart in phase, calculate the resultant.

C2= 1002 + 1002 - 2 * 100 * 100 * Cos(120)

C = 173 volts
 
You don't have enough info. You need to know the amplitude of the two AND:

1) For 2 space, you need the angle of one of them and know whether the other has angle greater or smaller.

2) For 3 space, you need both \theta, \phi\; of one and at least one angle of the second.

There might be some nifty trick that require less, but not just the angle between them.
 
vk6kro said:
You would need to know the magnitudes of the vectors.

Assuming you do know the magnitudes, you can either draw the vectors on graph paper and measure the resultant, or you can calculate it using the cosine rule:
http://en.wikipedia.org/wiki/Cosine_rule

For example, two 100 volt voltages are 120 degrees apart in phase, calculate the resultant.

C2= 1002 + 1002 - 2 * 100 * 100 * Cos(120)

C = 173 volts
But that is only relative only, I assume he mean you actually have to find the result vector from addition in absolute position and magnitude.( with specific \theta , \phi).
 
It is the voltage between phases of a 3 phase system.

What do you mean by "absolute position" with regard to voltages?
 
how to add two vectors knowing only angle between them for example if we have two vectors A and B having angle 40 degrees what will be the resultant sum of two?
also in three phase systems how to find resultant of two voltage of equal magnitude having a phase difference of 120 degrees

draw them and use the trigonometry you studied in high school ?

you need to do this repeatedly until it becomes as automatic as reciting the alphabet.
Drill , drill, drill !
 
vk6kro said:
It is the voltage between phases of a 3 phase system.

What do you mean by "absolute position" with regard to voltages?

He asked the vector question first, so I answer the question straightly as vector addition and not assuming anything even he ask another question about 3 phase. Particular he gave the example of 40 deg between the two vector, that don't trigger anything about 3 phase voltage. For vector addition, you need more info. Actually I have been doing vector calculus and addition of two vector in 3 space in spherical and rectangular coordinates is not that straight forward. Only in rectangular coordinates is straight forward.

Of cause if you look at in context of 3 phase, then it is easy. But is that what he really asking?
 
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also in three phase systems how to find resultant of two voltage of equal magnitude having a phase difference of 120 degrees

Seems clear enough that we are talking about 3 phase voltages.
 
how to add two vectors knowing only angle between them for example if we have two vectors A and B having angle 40 degrees what will be the resultant sum of two?This is the first question. And he asked about 40 degree, this don't spell anything about 3 phase voltage. I look at it as two different questions particularly if you read the tittle of the thread. I think you assume the two question is related. Until the op come back and clarify this, I don't think anyone should assume he only talk about 3 phase voltage. Vector happened to be a very important topics in EM and it is not that easy to add two vectors in spherical and cylindrical coordinate that use angle.
 
  • #10
yungman said:
how to add two vectors knowing only angle between them for example if we have two vectors A and B having angle 40 degrees what will be the resultant sum of two?


This is the first question. And he asked about 40 degree, this don't spell anything about 3 phase voltage. I look at it as two different questions particularly if you read the tittle of the thread. I think you assume the two question is related. Until the op come back and clarify this, I don't think anyone should assume he only talk about 3 phase voltage. Vector happened to be a very important topics in EM and it is not that easy to add two vectors in spherical and cylindrical coordinate that use angle.

No.
Question 1 was about vectors and we both answered that by saying it needed more information.
Question 2 was about voltages out of phase by 120 degrees. To solve these you could use the rule of cosines and I gave an example of solving a problem like his giving the result for some assumed voltages.
 
  • #11
vk6kro said:
You would need to know the magnitudes of the vectors.

Assuming you do know the magnitudes, you can either draw the vectors on graph paper and measure the resultant, or you can calculate it using the cosine rule:
http://en.wikipedia.org/wiki/Cosine_rule

For example, two 100 volt voltages are 120 degrees apart in phase, calculate the resultant.

C2= 1002 + 1002 - 2 * 100 * 100 * Cos(120)

C = 173 volts

You cannot use this to answer the first question. You cannot find the addition of two vector A and B just by specifying only the magnitudes AND the angle between them. You need more information as I explained.

How can you use the cosine law to find C?

I thought \vec B - \vec A = \vec C\;\Rightarrow\; |\vec C|^2 =|\vec A|^2+|\vec B |^2-2|\vec A||\vec B |\cos \theta

Cosine law is not to find magnitude of \vec C =\vec A +\vec B

\vec C = \vec A + \vec B\;\Rightarrow\;|\vec C|=\sqrt{(A_x+B_x)^2+(A_y+B_y)^2+(A_z+B_z)^2}

Get more complicate in sph and cyl coordinates.

And you cannot find \vec C\; with only the two amplitude and the angle between them.

I never even touch on the second question as I am not a power engineer.
 
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  • #12
Where is the problem? You can tell the magnitude of the resultant and its phase, referred to one of the vectors. How could anyone possibly expect to get more info out than that? The orientation of the original vectors in a reference frame is not given.
 
  • #13
Where is the problem? You can tell the magnitude of the resultant and its phase, referred to one of the vectors. How could anyone possibly expect to get more info out than that? The orientation of the original vectors in a reference frame is not given.
 
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