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- Homework Statement
- Find the work done by the gas (or on the gas) for an adiabatic process starting at V = 0.024 m^3 and 101325 Pa and ending at 0.0082 m^3 and 607950 Pa. The working gas is helium

- Relevant Equations
- Work for adiabatic = area under pV diagram

p1V1^gamma = p2V2^gamma

This is a relatively simple problem, but I'm not getting the right answer. For adiabatic compression, work on gas is positive, since work on gas = ΔEth and the adiabatic process moves from a lower isotherm to a higher one. Integrating for work gives:

pV * (V

I believe this is correct, but when I plug in the numbers, I'm getting a negative number:

101325 Pa * 0.024 m

= -3823.6 J

pV * (V

_{f}^{(1 - gamma)}- V_{i}^{(1 - gamma)})/(1-gamma)I believe this is correct, but when I plug in the numbers, I'm getting a negative number:

101325 Pa * 0.024 m

^{3}* ((0.0082 m^{3})^{1 - 1.67}- (0.024 m^{3})^{1 - 1.67})/(1 - 1.67)= -3823.6 J