Adiabatic vs. Isothermal Expansion: How to Calculate Work and Temperature?

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The discussion focuses on calculating work and temperature changes for an ideal monatomic gas undergoing adiabatic and isothermal expansions. The initial conditions include four moles of gas expanding from 1 m³ at 300 K to 10 m³. To find the work done during adiabatic expansion, the initial pressure can be calculated using the ideal gas law, which is essential for applying the work formula. The relationship between pressure and volume during adiabatic processes involves the heat capacity ratio (gamma), aiding in determining final pressure and temperature. For isothermal expansion, the source of energy for work done comes from heat absorbed by the gas.
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Hi people!
So i have a homework question that i am stuck on!

Four moles of an ideal monatomic gas undergoes an adiabatic expansion from intial volume of 1m cubed and a temperature of 300k to a final volume of 10m cubed. a) How much wrk is done by the gas ? b) what is the final temperature? c) If instead the gas expands isothermally to 10m cubed, how much work is done? d) In part C where does the energy come from to perform the work? ...thats a lot!

I thought of using the equation of work W(by)= 1/(1-gamma) x (PfVf-PiVi) to fnd the answer for a...but I don't have the pressure..:rolleyes: then i thought that maybe I could use deltaE= Q(in) - W (by)...but I don't know the change in temperature, therefore; I am all over the place and I don't know where to start.. any hints/help would be appreciated! Thanks
 
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With the information you were given, you can find the initial pressure of the gas.
 
bio87 said:
I thought of using the equation of work W(by)= 1/(1-gamma) x (PfVf-PiVi) to fnd the answer for a...but I don't have the pressure..:rolleyes:
First work out the initial pressure, which is easy since you are given n,Ti and Vi.
What is the relationship between P and V in an adiabatic expansion/compression? (hint: it involves \gamma). That will give you the final pressure and, if you know n, Vf and Pf you can determine Tf.

AM
 
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