jmatta
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Air balloon and ball question. HELP!
A balloon is going straight up at 21.5 m/s. You are in the balloon and you throw a ball at 13.2 m/s straight up while riding in the balloon. If the ball hits the ground at 34.5s
a) How long oes it take the ball to stop once it leaves your hand at the ball's highest point?
b) How high did the ball go after leaving your hand? (from your hand to the highest point)
c) How high off the ground did the ball go?
d) How fast was the ball traveling when it hit the ground? (Not zero)
e) How high off the ground was the ball when it was released
Vavg=(x/t)
x=1/2 (Vi+Vf)t
a= (Vf-Vi)/t
Vf=Vi + at
Vf^2= Vi^2 + 2ax
X= Vi t + 1/2(at)^2
a=-g=-9.81
a) Vi= 13.2 m/s g=9.81 Vf= 0m/s t=?
t= (Vf-Vi)/a
t= (13.2-0)/9.81
t= 1.35 Seconds
b) x= 1/2 (Vi+Vf) t
x= 1/2 (13.2) 1.35
x= 8.88 m
c) Not sure yet
d) A guess
Vf= -9.81 (34.5) + 0
Vf= -338.445 m/s
e) no idea
Any help/corrections are appreciated to better my understanding. Thank you
Homework Statement
A balloon is going straight up at 21.5 m/s. You are in the balloon and you throw a ball at 13.2 m/s straight up while riding in the balloon. If the ball hits the ground at 34.5s
a) How long oes it take the ball to stop once it leaves your hand at the ball's highest point?
b) How high did the ball go after leaving your hand? (from your hand to the highest point)
c) How high off the ground did the ball go?
d) How fast was the ball traveling when it hit the ground? (Not zero)
e) How high off the ground was the ball when it was released
Homework Equations
Vavg=(x/t)
x=1/2 (Vi+Vf)t
a= (Vf-Vi)/t
Vf=Vi + at
Vf^2= Vi^2 + 2ax
X= Vi t + 1/2(at)^2
a=-g=-9.81
The Attempt at a Solution
a) Vi= 13.2 m/s g=9.81 Vf= 0m/s t=?
t= (Vf-Vi)/a
t= (13.2-0)/9.81
t= 1.35 Seconds
b) x= 1/2 (Vi+Vf) t
x= 1/2 (13.2) 1.35
x= 8.88 m
c) Not sure yet
d) A guess
Vf= -9.81 (34.5) + 0
Vf= -338.445 m/s
e) no idea
Any help/corrections are appreciated to better my understanding. Thank you