- #1
jojoking
- 2
- 0
i have solved the question of a pebble thrown upwards without air resistance
speed 10m/s mass 0.02kg ma=w, w=-mg
man on cliff 50 feet high throws pebble upwards so it finishes in sea,
what height does it reach v=0 t = 10/g approx =1
since motion started at t =0 & duration of time 1s
x = 100/g - 100/2g is approx 5.1m so maximum height 55.1 m
BUT
i now need to find height with air resistance 0.008 v
any pointers to x value warmly recieved
cheersjk
speed 10m/s mass 0.02kg ma=w, w=-mg
man on cliff 50 feet high throws pebble upwards so it finishes in sea,
what height does it reach v=0 t = 10/g approx =1
since motion started at t =0 & duration of time 1s
x = 100/g - 100/2g is approx 5.1m so maximum height 55.1 m
BUT
i now need to find height with air resistance 0.008 v
any pointers to x value warmly recieved
cheersjk