Air speed in car radiator -- Heat Exchange calculations

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Discussion Overview

The discussion revolves around calculating the heat exchange area of a car radiator, specifically focusing on determining the external convection coefficient for air flow through the radiator. Participants explore the complexities of calculating air speed and convection coefficients in the context of forced convection.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • The original poster is using the equation Q = U*A*LMTD to calculate the heat exchange area and is uncertain about how to accurately determine the external convection coefficient due to the complexity of air speed calculations.
  • Some participants note that the air velocity is primarily influenced by the cooling fan and the vehicle's forward velocity, suggesting that ducting arrangements play a significant role.
  • One participant questions why the original poster is attempting to calculate U from flow rates when experimental data on Q and LMTD could suffice for determining U.
  • There is a suggestion that heat transfer correlations for air flow across finned tubes are available, but the original poster would need to conduct research to find these correlations.

Areas of Agreement / Disagreement

Participants express differing views on the approach to calculating the external convection coefficient and the necessity of calculating U experimentally versus theoretically. No consensus is reached on the best method to determine air speed through the radiator.

Contextual Notes

The discussion highlights the dependence on specific assumptions regarding ducting arrangements and fan characteristics, which may not be fully defined in the original poster's calculations.

r4m0n0
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Hello, this is my first post. This question is related to my final thesis.

I'm calculating the heat exchange area of a radiator through heat exchange equations:

Q = U*A*LMTD

I have as data Q, and LMTD (this one through trivial calculations)

In order to calculate U, I need the coefficients for external and internal (both tubes and fins) convection.
Internal convection coefficient is quite easy to calculate.
My doubts come when trying to calculate the external convection coefficient. As you may know to calculate the coefficient you need the Reynolds number (amongst other things).
Reynolds depends on the fluid speed (in this case air speed) and in order to calculate it I thought of the following equation:

v=(V_dot_air)/(no.of tubes*area of tubes) --->

The thing is... this calculation doesn't take in account the fins of the radiator, thus not having an accurate value for velocity.
But if I took in account the area of the fins into the equation, the velocity of air would be very VERY slow.

Can anyone suggest a better way to calculate air speed through a car radiator?

Thanks in advance :)
cross_flow_square_fins.png

(Image enclosed: a simplification of a car radiator)
 
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It's forced convection not natural convection .

Mass flow and velocity of cooling air is primarily determined by the cooling fan and possibly by forward velocity of vehicle depending on ducting arrangement .
 
If you have data on Q and LMTD, then you have enough to calculate U experimentally. So why are you trying to calculate it from the flows?

Chet
 
@Nidum:

Yes, it is forced convection, I never said otherwise. I'm calculating the air velocity "from scratch" so in order to know how the ducting arrangement and the cooling fan type/size I must calculate before the air velocity.

@Chestermiller:

Calculate U experimentally? Can you give me more insight on that? I have no physical model, everything is theorical.
 
r4m0n0 said:
Calculate U experimentally? Can you give me more insight on that? I have no physical model, everything is theorical.
Oh. You didn't say that. OK, how do you know the coolant flow rate to get the heat transfer coefficient on the tube side?

There are definitely heat transfer correlations available for air flow across banks of finned tubes. But you need to do the research yourself to find them.

Chet
 

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