Airplane and Wind Vector question

AI Thread Summary
An airplane flying south at 500 km/h is affected by a southwest wind blowing at 100 km/h. The resultant velocity of the plane relative to the ground is calculated to be 435 km/h, deviating 9.36 degrees east of south. The wind's components were determined using trigonometric functions, resulting in values of approximately 70.71 km/h for both x and y directions. The discussion highlights confusion about how to calculate the distance off course after 10 minutes without corrective action. Ultimately, the user expressed frustration over not receiving further assistance and decided to drop the course.
Avalonn
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Homework Statement



An airplane is heading due south at a speed of 500 km/h. If a wind begins blowing from the southwest at a speed of 100 km/h, calculate the velocity of the plane relative to the ground, and how far off course it will be after 10 min. if the pilot takes no corrective action.

Answer: 435 km/h, 9.36 degrees east of south


Homework Equations



x = hypotenuse * cos(45)
x = 100 km/h * cos(45)

y = hypotenuse * sin(45)
Y = 100 km/h * sin(45)

The Attempt at a Solution



First I drew a diagram with N, E, S, W labeled. I then drew a line going NE since the wind is coming from SW. Then using the same starting point as the wind I drew 500 km/h going south to represent the airplane. I now wrote in a 45 degree angle for the wind. From this point I made a right triangle for the wind. To find the x and y I used sin and cos to get the values y = 70.71 km/h and x = 70.71 km/h. Am I on the right track or no?
 
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Avalonn said:

Homework Statement



An airplane is heading due south at a speed of 500 km/h. If a wind begins blowing from the southwest at a speed of 100 km/h, calculate the velocity of the plane relative to the ground, and how far off course it will be after 10 min. if the pilot takes no corrective action.

Answer: 435 km/h, 9.36 degrees east of south


Homework Equations



x = hypotenuse * cos(45)
x = 100 km/h * cos(45)

y = hypotenuse * sin(45)
Y = 100 km/h * sin(45)

The Attempt at a Solution



First I drew a diagram with N, E, S, W labeled. I then drew a line going NE since the wind is coming from SW. Then using the same starting point as the wind I drew 500 km/h going south to represent the airplane. I now wrote in a 45 degree angle for the wind. From this point I made a right triangle for the wind. To find the x and y I used sin and cos to get the values y = 70.71 km/h and x = 70.71 km/h. Am I on the right track or no?

That's one good way to start. What next?
 
I am stumped. Where do I go from here?
 
After you get your velocity how do you find how the course of the plane movd in five minutes??
 
I don't know. I never got a reply and ended up dropping the course without having to pay for it fortunately.
 
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