Airplane Motion in Plane: West 900 km/h vs NE 300 km/h

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The discussion revolves around calculating the ground speed and direction of an airplane flying due west at 900 km/h while encountering a northeast wind of 300 km/h. Participants suggest using trigonometry, specifically the Sine and Cosine Rules, to resolve the non-right triangle formed by the airplane's motion and wind vector. The confusion arises from the non-right angle triangle, prompting the need for a clearer approach to vector addition. Visual aids, such as diagrams, are recommended to better understand the problem. Ultimately, the solution requires applying appropriate trigonometric methods to find the resultant direction and speed.
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Homework Statement


An airplane maintains a heading due west at an airspeed of 900 km/h. It is flyinh through a hurricane with winds of 300 km/h from northeast.
a) in which direction is the plane moving relative to the ground?

Homework Equations

The Attempt at a Solution


so I have draw the picture of how it looks, and written my givens down, this is confusing me because it is no longer a right angle triangle, what do I have to do?[/B]
 
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RENI2345 said:

Homework Statement


An airplane maintains a heading due west at an airspeed of 900 km/h. It is flyinh through a hurricane with winds of 300 km/h from northeast.
a) in which direction is the plane moving relative to the ground?

Homework Equations

The Attempt at a Solution


so I have draw the picture of how it looks, and written my givens down, this is confusing me because it is no longer a right angle triangle, what do I have to do?[/B]
Use trigonometry for non-right triangles.

Do you know the Sine Rule? The Cosine Rule?

http://www.cimt.plymouth.ac.uk/projects/mepres/step-up/sect4/index.htm

Scroll down a bit from the top.
 
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