Almost Commutative Property in Groups

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SUMMARY

The discussion centers on the property of groups where for elements g in group G and h in group H, there exists an element h' in H such that gh = h'g. This property is identified as a consequence of conjugation, where h' is defined as ghg^{-1}. The proof presented confirms that if G and H are normal subgroups of a group K with trivial intersection, an isomorphism θ(g,h) = gh exists for all g in G and h in H. The discussion concludes that while this property does not have a specific name, it is always true within the context of group theory.

PREREQUISITES
  • Understanding of group theory concepts, specifically normal subgroups.
  • Familiarity with the concept of conjugation in groups.
  • Knowledge of isomorphisms and their properties in algebra.
  • Basic proof techniques in abstract algebra.
NEXT STEPS
  • Study the properties of normal subgroups in group theory.
  • Learn about conjugation and its implications in group structures.
  • Explore isomorphisms in more depth, particularly in relation to group operations.
  • Investigate examples of groups where conjugation leads to interesting results.
USEFUL FOR

Mathematicians, particularly those specializing in abstract algebra, students studying group theory, and anyone interested in the properties of normal subgroups and conjugation in groups.

wnorman27
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Homework Statement


I'm trying to figure out if the following property has a name:

for g\in G, h\in H, \exists h'\in H s.t. gh=h'g.

obviously this is not quite commutativity, but it seems like it might be useful in a variety of situations.

Homework Equations



I've just finished a proof that if a group K has two normal subgroups G and H, whose intersection is just the identity, and whose join is K, then there exists an isomorphism θ(g,h)=gh for all g in G and all h in H. The key to proving surjectivity involved the fact that since H is normal, ghg^{-1} is also in H (call this h') so h=g^{-1}h'g and

gh=gg^{-1}h'g=h'g

The Attempt at a Solution


I think I've seen this discussed elsewhere, just can't remember the name. ----commutativity?
 
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wnorman27 said:

Homework Statement


I'm trying to figure out if the following property has a name:

for g\in G, h\in H, \exists h'\in H s.t. gh=h'g.

obviously this is not quite commutativity, but it seems like it might be useful in a variety of situations.
For H a group, the "property" that there exists such an h' doesn't have a name because it is always true! For any such g and h, h'= ghg^{-1} must exist. And that is saying that h and h' are conjugates. Perhaps that is what you are looking for.

Homework Equations



I've just finished a proof that if a group K has two normal subgroups G and H, whose intersection is just the identity, and whose join is K, then there exists an isomorphism θ(g,h)=gh for all g in G and all h in H. The key to proving surjectivity involved the fact that since H is normal, ghg^{-1} is also in H (call this h') so h=g^{-1}h'g and

gh=gg^{-1}h'g=h'g

The Attempt at a Solution


I think I've seen this discussed elsewhere, just can't remember the name. ----commutativity?
 
I understand that in the context of groups, this h' is just the result of conjugation of h by g, but my thought was that perhaps this might occur outside of the context groups (say in cases where inverses may not exist)? I can't think of any examples of this though... maybe this is just not useful.
 

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