Reacting Zn with .248M HCl to Produce H2

Thread starter kippy
Start date Sep 3, 2006
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To determine the volume of 0.248 M HCl required to react with 1.36 g of zinc to produce hydrogen gas, first, calculate the moles of zinc using its molar mass (approximately 65.38 g/mol). This results in about 0.0208 moles of zinc. The reaction between zinc and hydrochloric acid is a 1:2 molar ratio, meaning 0.0208 moles of zinc will require 0.0416 moles of HCl. Using the molarity of the HCl solution, the volume needed can be calculated by rearranging the molarity equation (M = moles/volume) to find volume = moles/M. This results in approximately 168.5 mL of 0.248 M HCl needed for the reaction.

Sep 3, 2006

kippy

How many milliters of .248 M HCl are needed to react with 1.36g of zinc to produce hydrogen gas

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Sep 3, 2006

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