Ambiguous Electric-Field magnitude

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The discussion revolves around calculating the electric field magnitude at point P on the x-axis due to two charges, +Q at x = -a and -Q at x = +a. The user derived the electric field equation as Ep = 4kQab/(b^2 - a^2)^2 but received feedback that their work was incorrect despite the teacher confirming the solution. There is confusion regarding the terms a^2 and b^2 in the equation, with a request for clarification on whether the contributions from both charges are equal. The direction of the electric field was determined to be towards the negative charge, indicating a rightward direction. Further assistance is sought to resolve the discrepancies in the calculations.
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Homework Statement


On the x axis, charge +Q lies at x = -a and charge -Q lies at x = +a. Point P lies on the axis at
x = +b, where b > a. a) Work out the electric field magnitude of P b) What is the direction of this …field?

Homework Equations


E=kqr/r3

The Attempt at a Solution


E=2kQa/(b2-a2) + 2kQa/(b2-a2)=
Ep=4kQab/(b^2 - a^2)^2. My teacher said that the solution was correct, however my work was not.
For b, I determined the direction to be to the right towards the negative charge.

I would appreciate any assistance.
 
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PHYHelp519 said:

Homework Statement


On the x axis, charge +Q lies at x = -a and charge -Q lies at x = +a. Point P lies on the axis at
x = +b, where b > a. a) Work out the electric field magnitude of P b) What is the direction of this …field?

Homework Equations


E=kqr/r3

The Attempt at a Solution


E=2kQa/(b2-a2) + 2kQa/(b2-a2)=
Ep=4kQab/(b^2 - a^2)^2. My teacher said that the solution was correct, however my work was not.
For b, I determined the direction to be to the right towards the negative charge.

I would appreciate any assistance.

The equation in red does not make sense. What are a2, b2? Do you mean that the contribution is the same from both charges?

ehild
 
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