Amount of energy rerquired to raise temperature

AI Thread Summary
To raise the temperature of 12.0 kg of water from 0 to 25 degrees Celsius, the energy required is calculated using the formula Q = m*c*ΔT, resulting in 1,257,000 Joules or approximately 300,286 calories. An alternative method using grams yields a similar result of about 300,000 calories. The choice between Joules and calories for the answer depends on the context or preference of the audience. Both methods confirm the energy requirement is consistent. Understanding the units of energy is crucial for accurate communication of results.
chaotiiic
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Homework Statement


What amount of energy is required to raise the temperature of 12.0 kg of water
from 0 degrees Celsius to 25 degrees Celsius?


Homework Equations


Q = m*c*ΔT
1 calorie = 4.186J
specific heat capacity for water = 4.19x10^3


The Attempt at a Solution


Q = m*c*ΔT = (12kg)(4.19x10^3)(25°) = 1,257,000J
1257000J/4.186 = 300,286 calories
 
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chaotiiic said:

Homework Statement


What amount of energy is required to raise the temperature of 12.0 kg of water
from 0 degrees Celsius to 25 degrees Celsius?


Homework Equations


Q = m*c*ΔT
1 calorie = 4.186J
specific heat capacity for water = 4.19x10^3


The Attempt at a Solution


Q = m*c*ΔT = (12kg)(4.19x10^3)(25°) = 1,257,000J
1257000J/4.186 = 300,286 calories

Did you have a question about your method or result?
 
gneill said:
Did you have a question about your method or result?
both.
another method i found online was to do (12000grams)*1cal/(g*K)*25 = 300,000 calories which is close to my first result. also i wasnt sure if the answer should be in joules or calories.
 
chaotiiic said:
both.
another method i found online was to do (12000grams)*1cal/(g*K)*25 = 300,000 calories which is close to my first result. also i wasnt sure if the answer should be in joules or calories.

Both methods amount to the same thing. As for the units of the result, that depends upon who is asking the question and what units they expect the answer to be in :smile: The calorie is a unit of energy, as is the Joule.
 
gneill said:
Both methods amount to the same thing. As for the units of the result, that depends upon who is asking the question and what units they expect the answer to be in :smile: The calorie is a unit of energy, as is the Joule.
ok thanks
 
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