An equilateral triangle w/3 =forces, 1/side,why is sum of torques always= at any pt?

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SUMMARY

The discussion centers on the calculation of torques in an equilateral triangle subjected to three equal forces. The key equation referenced is FLcos(30), where L represents the length of a side of the triangle. The confusion arises from the relationship between the distances of the forces and the height of the triangle, specifically how these distances do not always sum to the height. The participant ultimately resolves their confusion independently, indicating a deeper understanding of the torque calculations involved.

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  • Familiarity with trigonometric functions, particularly cosine.
  • Knowledge of equilateral triangle properties and geometry.
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mistymoon_38
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Homework Statement



and why is it FLcos(30)?

Homework Equations





The Attempt at a Solution


So by looking at the soln, D(distance)=Lcos(30), which should be the hieght of the traingle. But the distances between a the forces at any point don't always add up to the hieght.. I am confused
 
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Hi mistymoon_38,

mistymoon_38 said:

Homework Statement



and why is it FLcos(30)?

Homework Equations





The Attempt at a Solution


So by looking at the soln, D(distance)=Lcos(30), which should be the hieght of the traingle. But the distances between a the forces at any point don't always add up to the hieght.. I am confused

Could you provide more details about how the triangle and the forces are setup (are the forces acting on the midpoints of the sides, going out, or something else)? and about the calculation that you are talking about (as in where is the pivot point for the torque equation)?
 


i figured it out on my own. thanks anyways
 

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