An equilateral triangle w/3 =forces, 1/side,why is sum of torques always= at any pt?

AI Thread Summary
The discussion revolves around understanding the torque in an equilateral triangle with three forces acting on it. The confusion arises from the calculation of distances, specifically why D (distance) is represented as Lcos(30), which is thought to be the height of the triangle. Participants seek clarification on the setup of the forces and the pivot point used in the torque equation. Ultimately, one user resolves their confusion independently. The thread highlights the importance of accurately defining the geometry and forces when calculating torques.
mistymoon_38
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Homework Statement



and why is it FLcos(30)?

Homework Equations





The Attempt at a Solution


So by looking at the soln, D(distance)=Lcos(30), which should be the hieght of the traingle. But the distances between a the forces at any point don't always add up to the hieght.. I am confused
 
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Hi mistymoon_38,

mistymoon_38 said:

Homework Statement



and why is it FLcos(30)?

Homework Equations





The Attempt at a Solution


So by looking at the soln, D(distance)=Lcos(30), which should be the hieght of the traingle. But the distances between a the forces at any point don't always add up to the hieght.. I am confused

Could you provide more details about how the triangle and the forces are setup (are the forces acting on the midpoints of the sides, going out, or something else)? and about the calculation that you are talking about (as in where is the pivot point for the torque equation)?
 


i figured it out on my own. thanks anyways
 
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