Analysis of Wall Crane: Force & Moment at Pins A & D

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SUMMARY

The discussion focuses on analyzing the forces and moments acting on a wall crane, specifically at pins A and D, under a load of 800 N. The tension in the cable at the winch W is determined to be 400 N, while the tension in rod BD is calculated to be 490 N. However, discrepancies arise when calculating the tension TBD using moments at pin A, resulting in a value of 2752 N. The participants emphasize the importance of correctly applying equilibrium equations and moment calculations to resolve these inconsistencies.

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Homework Statement


The wall crane in Fig. 3 supports a load of 800 N. Determine the horizontal and vertical
components of reaction at the pins A and D. Also, what is the force in the cable at the winch
W?
[URL=http://imageshack.us][PLAIN]http://img182.imageshack.us/img182/992/tutorialse0.jpg[/URL] http://g.imageshack.us/g.php?h=182&i=tutorialse0.jpg [/PLAIN]


Homework Equations


Newton's Laws of Motion, Moment, Equilibrium of Forces


The Attempt at a Solution


First I draw a free body diagram at B. The vertical forces involved are the y component of the tension in rod BD and the y component of the tension of cable WB.

Since the tension of a massless cable is the same throughout the string, the tension of the cable is 400N. Substituting the value of TWB to the above equation, I get TBD=490N.

However, a problem occurs when I attempt to find TBD by taking the moment at A. The solution for TBD turns out to be 2752N.

What cause the difference in the answer?
 
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I think it will be easier for us to see where you went wrong if you would show some work with regard to the step on substituting the value of Twb.

My suggestion to get Tbd, now that you have the tension in the rope right is to take the moments at A. The sum of moments must be zero. You have a 800N weight acting at 2 meters CW, and Tbw acting at 1 meter at a 60 degree angle CW. The counter moment CCW then must be Dx.
 

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