Angular acceleration of a rock, in a tire, on a car

[deathcap00]

Homework Statement

A rock is wedged into the treads of a 15 in radius tire. The car to which it is attached is driving down the road at 70mph.
What’s the angular acceleration of the rock?

Homework Equations

a_r=- \omega₀²r

The Attempt at a Solution

Not sure where to begin really, how does the car's speed influence the angular acceleration of the rock? What are the basic steps to take to set this problem up?

 

[xcvxcvvc]

Homework Statement

A rock is wedged into the treads of a 15 in radius tire. The car to which it is attached is driving down the road at 70mph.
What’s the angular acceleration of the rock?

Homework Equations

a_r=- \omega₀²r

The Attempt at a Solution

Not sure where to begin really, how does the car's speed influence the angular acceleration of the rock? What are the basic steps to take to set this problem up?

angular velocity is the rate of change in angle. Angular acceleration is the rate of change in angular velocity. If a tire is traveling at a constant linear velocity, then its angular velocity must be constant.

\frac{d\omega}{dt} = \alpha. What is the derivative of a constant? If you do not know calculus, what would the rate of change in velocity be if velocity was constant?

 

[deathcap00]

angular velocity is the rate of change in angle. Angular acceleration is the rate of change in angular velocity. If a tire is traveling at a constant linear velocity, then its angular velocity must be constant.

\frac{d\omega}{dt} = \alpha. What is the derivative of a constant? If you do not know calculus, what would the rate of change in velocity be if velocity was constant?

Is my angle 2*pi?

do I need to convert the radius of the tire to miles (or the miles/hr to ft/s)?

and the derivative of a constant is zero

 

[xcvxcvvc]

Is my angle 2*pi?

do I need to convert the radius of the tire to miles (or the miles/hr to ft/s)?

and the derivative of a constant is zero

The car is spinning at a constant angular velocity to sustain a constant linear velocity. The rock is doing whatever the tire is doing. The rock then has constant angular velocity. With constant angular velocity, angular acceleration is zero.

 

[deathcap00]

The car is spinning at a constant angular velocity to sustain a constant linear velocity. The rock is doing whatever the tire is doing. The rock then has constant angular velocity. With constant angular velocity, angular acceleration is zero.

So my answer is zero then, that would explain why my professor said that he meant to ask for radial acceleration (but said he would accept angular as well though).

Just for the sake of knowing, how would I find the radial acceleration of the rock?

Thanks so much for your help.

 

[xcvxcvvc]

So my answer is zero then, that would explain why my professor said that he meant to ask for radial acceleration (but said he would accept angular as well though).

Just for the sake of knowing, how would I find the radial acceleration of the rock?

Thanks so much for your help.

We know to relate an angular value to a linear value, we multiply by the radius from the center of rotation. To remember this equation, note that the units make sense.
rad => meter
rad/s => m/s
rad/s^2 => m/s^2

So we can either divide your linear velocity by radius to find \omega and use
a_r = \omega^2 r
or we can multiply
a_r = \omega^2 r
by \frac{r}{r}
and use the above rules to change the equation to
a_r = \frac{v^2}{r}
where v is the linear velocity. Then we can use that equation. It's just simple plug n' chug.

 

[ideasrule]

Radial acceleration is a=v^2/r.

 

[deathcap00]

thank you both very much!