Angular acceleration of a solid uniform cylinder

AI Thread Summary
When a string is pulled tangentially on a solid uniform cylinder, it produces angular acceleration. If the cylinder's radius is doubled while keeping other factors constant, the relationship between radius and angular acceleration must be considered. The confusion arises from the relationship between radius and diameter; doubling the radius does not quadruple the angular acceleration. The correct answer to the question posed is 2*alpha, as the angular acceleration is inversely proportional to the radius. Understanding these principles is crucial for solving problems involving rotational dynamics.
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String is wrapped around the outer rim of a solid uniform cylinder that is free to rotate about a frictionless axle through its center. When the string is pulled with a force P tangent to the rim it gives the cylinder an angular acceleration alpha. If the cylinder had twice the radius, but everything else was the same, the angular acceleration would be
A) 4*alpha
B) 2*alpha
C) alpha/2
D) alpha/4

Wouldn't it be 4 times, since the diameter is now four times as large?
 
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If the radius is doubled, the diameter is also doubled, not quadrupled.
 
Oh right, haha. So would it just be 2*alpha or is this a trick question?
 
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