Angular and linear velocity of a rigid body given a force.

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SUMMARY

The discussion centers on calculating the angular velocity (ω) and linear velocity (v) of a rigid body, specifically a cube with sides of 1, mass of 1, and a center of mass (c.o.m.) at (0,0,0.5), subjected to a force of 10 along the x-axis. The user proposes the formula ω = I-1Lp, where I-1 is the inverse of the inertia tensor and Lp is the angular momentum. The angular momentum is defined as Lp = s x Mv, with s being the position vector relative to the c.o.m., M the mass, and v the velocity of the c.o.m. The discussion also addresses a confusion regarding the c.o.m. position being on the xy plane.

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calvinwylie
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Hello,

I'm trying to prove a simulation of mine is working correctly. the simulation has a cube of sides 1, mass 1 and c.o.m. position at (0,0,0.5) ie sitting on the xy plane. i have a force along the x-axis of 10. Is there anyway given those two, that i can work out the resulting ω and v of the body? the cube is unconstrained.

this is my first post, so if I've done something wrong i apologise.

Thanks
 
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ok so i think I've found this:

ω = I-1Lp

where I-1 is the inverse of the inertia tensor. Lp is the angular momentum of the point the force is exerted on.

Lp = s x Mv.

where s is the position vector of the point relative to the center of mass. M is mass of the object and v is the velocity of the com.

Can someone at least tell me if this is correct?
 
calvinwylie said:
Hello,

I'm trying to prove a simulation of mine is working correctly. the simulation has a cube of sides 1, mass 1 and c.o.m. position at (0,0,0.5) ie sitting on the xy plane. i have a force along the x-axis of 10.
Thanks

How is (0,0,0.5) on the xy plane? One ussually takes the order (x,y,z)
 

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