Angular Deceleration of Flywheel due to Rotation Motion

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The discussion revolves around calculating the angular deceleration of a flywheel that stops after 12 revolutions. The initial angular velocity is converted to 18.9 rad/s, and the time to stop was initially miscalculated as 4 seconds. Participants clarify that the average angular speed should be used to determine the correct time, leading to a recalculation of time as approximately 8 seconds. The final angular deceleration is calculated to be -2.37 rad/s². The importance of using average speed in rotational motion calculations is emphasized throughout the discussion.
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Homework Statement



A flywheel of radius 0.20 m with moment of inertia 0.15 kg/m^2 rotates at 180 revolution per minute . A tangential force is applied on the rim of the flywheel and it stops after 12 revolutions.Calculate the angular deceleration .

Homework Equations





The Attempt at a Solution



The initial angular velocity is 18.9 rad/s after conversion. The time taken for 12 revolutions is 4s (since it can rotate 180 times in 60 s , so in 4 s , it can rotate 12 times) . Final angular velocity is 0 .

Using \omega_f=\omega_i+\alpha t

0=18.9+4\alpha

solving this , i got 4.37 sec

but the ans given 2.37 sec, where did i go wrong ?
 
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thereddevils said:
The time taken for 12 revolutions is 4s (since it can rotate 180 times in 60 s , so in 4 s , it can rotate 12 times) .
That would be true if the angular velocity were constant, but it's not. The wheel is slowing down. Hint: What's the average speed during its acceleration?
 
Doc Al said:
That would be true if the angular velocity were constant, but it's not. The wheel is slowing down. Hint: What's the average speed during its acceleration?

thanks Doctor , so if i take the average velocity , then the time,t =4s would be valid in my calculations ?

a=v/t=(18.9/2)/4=2.37
 
thereddevils said:
thanks Doctor , so if i take the average velocity , then the time,t =4s would be valid in my calculations ?
The thing to do is use the average angular speed to find the correct time. (4s is not correct.) Then you can use your original equation to find the acceleration.
 
Doc Al said:
The thing to do is use the average angular speed to find the correct time. (4s is not correct.) Then you can use your original equation to find the acceleration.

sorry doc , i still don get it .

Is the average simply 18.9/2=9.45 s

Then , i am not sure how to use this to find time .
 
thereddevils said:
sorry doc , i still don get it .

Is the average simply 18.9/2=9.45 s
Yes. (The units are radians/sec.)

Then , i am not sure how to use this to find time .
Use the rotational analog to Distance = Ave Speed X Time
(The "distance" will be the angle in radians.)
 
Doc Al said:
Yes. (The units are radians/sec.)


Use the rotational analog to Distance = Ave Speed X Time
(The "distance" will be the angle in radians.)

thanks i was too hung up with the 180 revolutions as compared to 12 revolutions so a final check ,

the angular displacement is 2pi x 12=75.4 (Initially , i though of 2pi x 0.2 x12 , this would be linear displacement right ?)

75.4=9.45t , t is approximately 8s .

0=18.9+8a

a=-2.37 rad/s^2
 
All good! :approve:
 
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