Frictional Forces on a Rotating System and Disk: Understanding Angular Momentum

AI Thread Summary
The discussion centers on the frictional forces acting on a rotating system when a metal disk is dropped onto it. Initially, there is confusion about the direction of the frictional force, with some believing it acts counter-clockwise on the disk and clockwise on the system. However, it is clarified that when the disk is dropped, it is not rotating, and friction will cause it to rotate in the same direction as the system, which is clockwise. Consequently, the frictional force acts clockwise on the disk and counter-clockwise on the system, leading to a slowdown of the system. This understanding emphasizes the relationship between friction, rotation, and angular momentum in the described scenario.
NasuSama
Messages
323
Reaction score
3

Homework Statement



Suppose the system is rotating clockwise when the metal disk is dropped on it. The direction of the frictional force is...

zero on the disk and the system
counter-clockwise on the disk, clockwise on the system
clockwise on the disk, zero on the system
counter-clockwise on the disk zero on the system
zero on the disk, clockwise on the system
clockwise on the disk and the system
counter-clockwise on the disk and the system
clockwise on the disk, counter-clockwise on the system
zero on the disk, counter-clockwise on the system

2. The attempt at a solution

I believe that the answer is:

"counter-clockwise on the disk, clockwise on the system"

But it is not right. I thought that a system keeps turning clockwise, and that when a disk is place on the system, then the frictional force acts counter-clockwise on the disk.
 
Physics news on Phys.org
If that is the entire description you're given, I agree with you. Is there more?
 
See:

http://www.physics.qc.edu/files

Check under PH. 145.1 Then, check Trial 1 under the Procedures.

That describes the experiment, which is related to the question I'm asked.
 
This is strange. I read the OP several times before saying I agree with you, but reading it again I don't! Must have got something backwards before.
When the disk is dropped on it is not rotating. Friction will lead to its rotating in the same direction as the system, clockwise. So the force must be clockwise on the disc (and the other way on the system).
 
haruspex said:
This is strange. I read the OP several times before saying I agree with you, but reading it again I don't! Must have got something backwards before.
When the disk is dropped on it is not rotating. Friction will lead to its rotating in the same direction as the system, clockwise. So the force must be clockwise on the disc (and the other way on the system).

That means frictional force goes clockwise while the system goes counterclockwise?
 
NasuSama said:
That means frictional force goes clockwise while the system goes counterclockwise?
In the lab described, the system will tend to slow down when the disk is dropped on it. Therefore friction acts on the system counter to the system's motion.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top