Angular Momentum of an airplane

AI Thread Summary
The discussion focuses on calculating the angular momentum of a 12,000 kg airplane flying at 175 m/s at an altitude of 10 km. The formula for angular momentum, L = r × mv, is applied, with r representing the altitude. The initial calculation suggests L = 21,000,000 kg·m²/s, but there is uncertainty about the correctness of this value. Participants also mention the relevance of other equations, such as I = (2/5)Mr², and discuss the relationship between linear velocity and angular momentum. The value of angular momentum remains constant as the airplane moves in a straight line.
lunarskull
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An airplane of mass 12000kg flies level to the ground at an altitude of 10. km with a constant speed of 175 m/s relative to the earth. (a) what is the magnitude of the airplane's angular momentum relative to a ground observer directly below the airplane? (b) Does this value change as the airplane continues its motion along a straight line?

desperate...was out with the flu now I am lost :confused:
so L= r X Mv...
L=r??X (12000)(175)
r=10??
so 10X(12000)(175)
21000000. this doesn't look correct...
 
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What equations do you know that relate linear velocity with angluar momentum (assuming the Earth is spherical)
 
Hootenanny said:
What equations do you know that relate linear velocity with angluar momentum (assuming the Earth is spherical)

just edited first post. i guess maybe
I=(2/5)Mr^2 might come in handy?
 
L = Mvr would be easier to use with regards to the plane, where r is the radius of orbit and v is linear velocity.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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