What is the Angular Momentum of Harry Potter on a Spinning Merry-Go-Round?

AI Thread Summary
Harry Potter, positioned 2.0 meters from the center of a spinning merry-go-round, has a mass of 50.0 kg and can endure an acceleration of up to 5g before losing consciousness. To determine his angular momentum at the point of passing out, the relevant equations are L = mvr and the relationship between centripetal acceleration (a = v^2/r). By equating the maximum acceleration (5g) to the centripetal acceleration, the velocity (v) can be calculated. Once v is determined, it can be substituted back into the angular momentum equation to find the magnitude of Harry's angular momentum. The discussion highlights the importance of understanding the relationship between acceleration, velocity, and angular momentum in this scenario.
bazookajason
Messages
9
Reaction score
0

Homework Statement


Harry Potter is sitting 2.0 meters from the center of a merry-go-round when Draco Malfoy casts a spell that glues
Harry in place and then makes the merry-go-round start spinning on its axis. Harry has a mass of 50.0 kg and can
withstand 5:0 g's of acceleration before passing out. What is the magnitude of Harry's angular momentum when
he passes out?


Homework Equations


T=I alpha
L=mvr


The Attempt at a Solution



Assuming that the spell is a force then rF = I alpha. And using alpha = a/r, we using the max acceleration of 5g that
5mgr = Ia/r
However I'm not sure where to go from this, how do i get v? as time is unknwon
 
Physics news on Phys.org
bazookajason said:

Homework Statement


Harry Potter is sitting 2.0 meters from the center of a merry-go-round when Draco Malfoy casts a spell that glues
Harry in place and then makes the merry-go-round start spinning on its axis. Harry has a mass of 50.0 kg and can
withstand 5:0 g's of acceleration before passing out. What is the magnitude of Harry's angular momentum when
he passes out?

Lets look at the second eqn you mentioned,
L=mvr
you have m,r. what you need is v

Now, what do you think the acceleration 5g is acting along (direction)?
 
oh i see mv^2/r = ma a=5g :D
thanks!
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top