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HobieDude16
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well, I've tried, and I've tried, but i can't seem to get this one right, my TA did it in class, but left something out i think, he did it in a big hurry, so i can't get an answer that's right... ill show you what I've tried, and maybe you can spot my error? any help is much appreciated
Figure 11-49 is an overhead view of a thin uniform rod of length 0.600 m and mass M that is rotating horizontally at 80.5 rad/s counterclockwise about an axis through its center. A particle of mass M/3.00 and speed 41.5 m/s hits the rod and sticks. The particle's path is perpendicular to the rod at the instant of the hit, at a distance d from the rod's center.
(a) At what value of d are rod and particle stationary after the hit?
m
ok, so our ta worked out the cross produt of r and the particle, and used that to get the equation (1/12)mL^2 omega^2-d(m/3)v=0... so you sove that out, and get d=(L^2omega^2)/4v but that's just not right... what am i doing wrong? any help? thanks in advance
John
Figure 11-49 is an overhead view of a thin uniform rod of length 0.600 m and mass M that is rotating horizontally at 80.5 rad/s counterclockwise about an axis through its center. A particle of mass M/3.00 and speed 41.5 m/s hits the rod and sticks. The particle's path is perpendicular to the rod at the instant of the hit, at a distance d from the rod's center.
(a) At what value of d are rod and particle stationary after the hit?
m
ok, so our ta worked out the cross produt of r and the particle, and used that to get the equation (1/12)mL^2 omega^2-d(m/3)v=0... so you sove that out, and get d=(L^2omega^2)/4v but that's just not right... what am i doing wrong? any help? thanks in advance
John
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