Angular Velocity: Find Launch Angles for Projectile

AI Thread Summary
To determine the launch angles for a projectile traveling 100 m horizontally and clearing a 10 m wall, the equations of motion must be applied separately in the horizontal and vertical directions. The horizontal motion is governed by the equation x = v0t, while the vertical motion can be analyzed using y = v0t - (1/2)gt^2. By eliminating time from these equations, a quadratic equation in terms of the launch angle θ can be derived, yielding two possible solutions for the angle. The discussion emphasizes the importance of using constant acceleration equations to find these angles. Ultimately, the goal is to identify the two launch angles that allow the projectile to just clear the wall.
trigunesq
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Homework Statement


A projectile is launched at 36 m/s and travels 100 m horizontally. If it is to be able to just barely clear a 10 m wall, between what two angles should the projectile be launched with respect to the horizontal?




Homework Equations


vf=vo+at
x=vot+1/2at^2
vf^2=Vo^2+2ax
 
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Welcome to PF!

Hi trigunesq! Welcome to PF! :smile:

(have a theta: θ and try using the X2 and X2 tags just above the Reply box :wink:)

They're asking you for the two angles from which it will be 10m up when it's 100m along.

Call the launch angle θ, and the time taken t, then use your constant acceleration equations for the x and y directions separately (a = 0 for the direction, of course), to get a pair of equations from which you can eliminate t to get a quadratic equation for θ (with two solutions! :wink:).

What do you get? :smile:​
 

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