Angular Velocity Homework: Calculating Higher Derivatives

AI Thread Summary
The discussion focuses on calculating angular velocity and acceleration from knee angle data in cycling, specifically at an angle of 119.1 degrees. Participants clarify that with a sampling frequency of 50 Hz, each measurement is taken every 0.02 seconds. The angular velocity is computed as 230 degrees per second, derived from the average of the changes in angle over time. Additionally, the acceleration is calculated as -1500 m/s², indicating a decrease in velocity. A key issue raised is the challenge of calculating higher derivatives from sampled data, which can lead to inaccuracies due to noise and limited data resolution.
clokey34
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Homework Statement



The following data are for the angular displacement of the knee in cycling
measured in degrees. Using radian measure, compute the angular velocity
and acceleration when the knee angle is 119.1 degrees. The sampling
frequency was 50 Hz. What is a problem you may encounter when calculating
higher derivatives from sampled displacement data?
98.0, 103.5, 109.0, 114.2, 119.1, 123.4, 126.9


Homework Equations



Angular velocity is degrees per unit time.


The Attempt at a Solution



I only have the angle. And a frequency but not a discrete time variable? Thanks!
 
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clokey34 said:
And a frequency but not a discrete time variable?
What is the definition of frequency? :wink:
 
Yeah I agree it is 50 cycles a second but then I'm not sure how to apply that?
 
clokey34 said:
Yeah I agree it is 50 cycles a second but then I'm not sure how to apply that?
So, you know that every second there are fifty measurements taken. Equally, you know that each measurement is separated by 1/50 = 0.02 seconds.

Can you go from here?
 
Oh right you make it so simple! Thanks.

So change in velocity over change in time. Change in time is 0.02sec

change before
119.1 -114.2 = 4.9deg
4.9/0.02=245deg

change after
123.4 - 119.1 = 4.3deg
4.3/0.02=215deg

(245+215)/2= 230deg.sec-1

Accel= change of rate of velocity is (230-245)/2
=-1500ms-2
 
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