SOLVED: Angular velocity of an electron 1. The Bohr model of the hydrogen atom pictures the electron as a tiny particle moving in a circular orbit about a stationary proton. In the n = 2 orbit the distance from the proton to the electron is 21.16*10^-11 m, and the linear speed of the electron is 1.09*10^6 m/s. 2. What is the angular velocity of the electron? 3. To find the angular acceleration (ω), I started with v=rω (linear velocity=radius*angular velocity) and arranged it to solve for ω (ω=v/r). Plugging the given values in, I came up with ω=1.09*10^6/21.16*10^-11, and I got 2.43*10^14 (and 5.15*10^15 as well, for some reason) for an answer, which is wrong according to WebAssign. I'm down to my last submission and would really appreciate it if someone could point out what I'm doing wrong.