Angular Velocity of Hand Crank & Axle

AI Thread Summary
The discussion confirms that the angular velocity of the hand crank and the axle are indeed the same when the crank is turned. It clarifies that the linear velocity of the axle at its edge is calculated using the formula ωr, which equals the velocity of the bucket being lowered. Participants agree on the relationship between the angular and linear velocities in this mechanical setup. The conversation also addresses language concerns, emphasizing clarity in technical discussions. Overall, the mechanics of the hand crank and axle system are accurately described.
hippolyta2078795
Messages
12
Reaction score
0
I have a problem involving a hand crank, an axle, and a bucket. The crank turns the axle. The axle lowers the bucket. When someone spins a hand crank, the angular velocity of the hand crank and the axle are the same right? I think it and they seem to be the same.

The velocity of the bucket equals the linear velocity of the axle. Correct.

Sorry if my English isn't good as it is not my first language.
 
Physics news on Phys.org
Yes, the angular velocity of the crank and axle are the same, as you stated.
The linear velocity of the axle at it's edge would be \omega r, which would be equal to the velocity of the bucket.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'

Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'

Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is（Figure 2）： F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Comparison between two Tippe tops
Replies
1
Views
631
What is the Angular Velocity Acquired by a Disk on a Rotating Platform?
Replies
28
Views
4K
Analyzing the Mechanics of a Wobble Plate in a Cranked Axle Mechanism
Replies
10
Views
3K
Angular Momentum- Conserved or not?
Replies
17
Views
363
What is the rotational velocity of the crank?
Replies
3
Views
5K
Why did I get this angular momentum problem wrong?
Replies
25
Views
11K
Angular Acceleration of a Wheel on a Turntable
Replies
2
Views
7K
Perfectly inelastic collision of two moving and rotating disks
Replies
9
Views
2K
How Can Angular Momentum Principles Solve Disk Rotation Problems?
Replies
1
Views
3K
Maximum angular velocity so that there is no stick
Replies
9
Views
2K

Hot Threads

Recent Insights

Back
Top