The Hubble Space Telescope is poered by two solar panels as shown. The body of the telescope has a mass of 11 Mg and a radii of gyration kx = 1.64m and ky = 3.85m, whereas the solar panels can be considered as thin plates, eac having a mass of 54 kg. due to an internal drive, the panels are given an angular vlocity of .6j rad/s measured relative to the telescope. Determine the angular velocity of the telescope due to the rotation of the panels. Prior to roatin the panels, the telescope was originally traveling at vg = -400i + 250j + 175k m/s
The Attempt at a Solution
G--> m = 11,000 kg, kx = 1.64m, ky = 3.85m, vinitail = -400i + 250j + 175k m/s
Panels--> 6m X 1.5m, m = 54 kg each, w = .6j rad/s
mtotal = 11,000 + 2(54) = 11108 kg
Ix = mkx2 = 11108(1.64)2 = 29876.0768
Iy = mky2 = 11108(3.85)2 = 163794.1248
Should i then use principle of impulse and momentum by doing for each axis.