Angular Velocity: Formula for Max Velocity of Wood Block

AI Thread Summary
To determine the maximum velocity of a wood block moving on a steel plate, the angle θ must be optimized based on the plate's velocity v. The block's velocity in the direction of interest (B) can be expressed as V_B = vcos(θ)sin(θ). To find the angle that maximizes this velocity, differentiate the expression with respect to θ and set the derivative to zero. Alternatively, trigonometric methods can also be employed to find the maximum value of V_B. Understanding these calculations requires a basic knowledge of calculus.
Brett bALL
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This is my first contact and please excuse my limited knowledge of physics.
see attached sketch.
If the steel plate is moved along the steel table in direction A at a given velocity, what is the formula for the angle to achieve maximum velocity of the wood block in direction B.
 

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Hi,

Im assuming that you have a basic knowledge of calculus.

If you assume that the plate moves in the direction A with a velocity v, then the block moves with a velocity vcos(\theta) along the plank in the downward direction.

The projection of this velocity along the B and A direction is vcos\thetasin\theta and vcos\thetacos\theta

V_B=vcos(\theta)sin(\theta)
Differentiate this expression wrt \theta and equate to zero to get max value.

Otherwise, you can find the max value of Vb using trig.
 
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