Another Friction Equilibrium Problem

AI Thread Summary
The discussion revolves around solving a friction equilibrium problem involving a three-force member, where the forces' lines of action intersect at a point. Participants suggest drawing tangents at contact points to establish equilibrium equations. The relevance of the 4m length is debated, particularly in calculating component angles at contact points. A formula for chord length in circular sections is introduced to help determine angles subtended at the circle's center. The calculated angle of 101.61 degrees is confirmed by multiple contributors.
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Homework Statement



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Homework Equations


Sum of forces in X, Y, f/n= coefficient of friction


The Attempt at a Solution



I tried looking at this as a 3 force member, since the lines of action of the normals and the weight intersect at a point, but I am not sure where to go from there. Or where the 4m length comes into play.
 
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I think what you need to do is draw in the tangents at the points of contact and that should give you the basic equation that balances the piece and keeps it in equilibrium.

Where the diameter and length comes in I think is in determining what the component angles are at the contact points.

I think using the relationship that a chord length of a circular section is given by

C = 2*R*Sin(θ/2)

You can calculate the angle that the bar subtends at the center of the circle and then you should be able to calculate those angles.

(See: http://mathworld.wolfram.com/CircularSegment.html )
 
Hmm, I've never seen that forumla before. Does it work when the "c" is slanted anywhere? So did, I use that eqaution correctly? I got theta = 101.61 degrees
 
Last edited:
I got it from the link I supplied.

Looks like 101.6 degrees to me as well.
 
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