When will the pilot hit the ground while flying over sloping terrain?

AI Thread Summary
A pilot flying horizontally at 1300 km/hr at a height of 35m begins to fly over ground sloping upward at an angle of 4.3 degrees. To determine when the pilot will hit the ground, a right triangle can be drawn, with the vertical side representing the height and the angle opposite to it being 4.3 degrees. Using trigonometry, the horizontal distance to the point of impact can be calculated, which is approximately 470m. Given the plane's speed of 361m/s, the time to impact is calculated to be about 1.3 seconds. The approach taken effectively combines kinematics and trigonometric principles to solve the problem.
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Homework Statement


A pilot flies horizontally at 1300 km/hr at height 35m above initially level ground. At t= 0 the pilot begins to fly over ground sloping upward at an angle of 4.3 degrees. If the pilot does not change his heading, at what time will he hit the ground?


Homework Equations



Kinematics equations, and maybe trig.

The Attempt at a Solution



I have two ideas on how to start this problem. First was to think of the plane as going down at the angle of 4.3 degrees and the ground being flat and draw a triangle. But I felt like I was on the wrong track.
Then I was thinking to think of the airplane as sitting still, and the ground coming up toward it a 4.3 degrees and 1300 km/hr.

Are either of these the right way to solve this problem?
Thanks
 
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You can try solving the way you suggest, but you may get confused. There is more straightforward way. Draw yourself a right triangle with one side vertical and equal to 35 m and with the angle opposite to it equal to 4.3 degrees. Can you calculate the length of the other right side that is horizontal? If so, find the time it takes the plane to travel that horizontal distance.
 
Always a good idea to draw a picture exactly related to the question. You can always take shortcuts later after youv'e done infinity of these types of problems. I'm imagining a right triangle in your future with one of the three angles equal to 90-4.3 degrees. You should be able to find the distance the plane will travel using trig, as you correctly asserted. Then its a matter of using the constant velocity equation d=r*t.

[edit: I don't even have a cool picture. I'll go to bed now.]
 
2m6sqar.jpg


My trig is a little rusty, but I think I can use the law of sines to get the horizontal magnitude.

\frac{L}{sin85.7}=\frac{35}{sin4.3}

L\approx470m

The plane is moving at 361m/s, so

\frac{470m}{361m/s}\approx1.3s

Does that look right?
 
Yes. Good job.
 
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