How Do You Calculate Acceleration and Retardation for a Train's Movement?

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To calculate acceleration and retardation for a train's movement, the train accelerates uniformly from rest to 54 km/h in 200 seconds, resulting in an acceleration of 972 km/h². During the next 300 seconds, the train maintains a constant speed, indicating zero acceleration. Finally, the train decelerates to rest over 150 seconds, which can be calculated similarly to the initial acceleration phase. The key equations used include s = ut, v = u + at, and s = ut + 0.5at². Understanding these concepts is essential for solving problems related to train movement dynamics.
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Homework Statement


A train accelirates uniformly from rest to reach a speed of 54km/hr in 200 seconds after which the speed remains constant for 300 seconds, At the end of this time the train decelerates to rest in 150 seconds.

Calculate the acceleration and retardation.

Homework Equations


s= ut
v= u+at
s=ut + 0.5*at^2

The Attempt at a Solution



a = (v-u)/t = 54/(200/60*60)=972km/h^2

is the first part correct? I'm not really sure what to do next.
 
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First part is correct; in second part speed is constant, hence no acceleration and third part is similar to first part.
 

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