Another problem with kirchhoff's law and parallel cells

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SUMMARY

This discussion centers on the application of Kirchhoff's laws to calculate the current in a 2-ohm resistor within a parallel circuit configuration. The user derived the equation i3 = i1 - i2 and applied Kirchhoff's voltage law, resulting in the equation 1 - 2(i1 - i2) + 2.i2 = 0. Despite calculating a current of 0.375A for i2, the textbook states the answer is 0.42A. The consensus confirms the user's calculations are accurate, indicating a potential error in the textbook.

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alexburns1991
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Homework Statement



Using kirchhoff's laws, calculate the current in the 2 ohm resistor.
Picture of the circuit attached.

Homework Equations



kirchhoff's laws, and ohms law

The Attempt at a Solution



i3 = i1 - i2

then i used kirchhoff's law to get:
2 - i1 = 2.i2
and
1 - 2 ( i1 - i2 ) + 2.i2 = 0 [i added the value because the direction of the "potential walk" is opposite to the current through the resistor]

using these, i obtained a value of 0.375A as the current i2, but the book says that the answer is 0.42A, have i made a mistake, or is the book wrong [again!]?
 

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Your solution is correct.

ehild
 

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