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Another problem with kirchhoff's law and parallel cells

  1. Sep 15, 2009 #1
    1. The problem statement, all variables and given/known data

    Using kirchhoff's laws, calculate the current in the 2 ohm resistor.
    Picture of the circuit attached.

    2. Relevant equations

    kirchhoff's laws, and ohms law

    3. The attempt at a solution

    i3 = i1 - i2

    then i used kirchhoff's law to get:
    2 - i1 = 2.i2
    1 - 2 ( i1 - i2 ) + 2.i2 = 0 [i added the value because the direction of the "potential walk" is opposite to the current through the resistor]

    using these, i obtained a value of 0.375A as the current i2, but the book says that the answer is 0.42A, have i made a mistake, or is the book wrong [again!]?

    Attached Files:

  2. jcsd
  3. Sep 15, 2009 #2


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    Homework Helper

    Your solution is correct.

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