the question is [tex]\int 2x sec^2 (x^2) dx[/tex](adsbygoogle = window.adsbygoogle || []).push({});

do i sub u= sec (x^2) ?

I so far have got to trying to sub u= sec(x^2) and getting du= 2 (sec x^2 tan x^2)... i have a strong feeling i fudged the "du" part. hmm.

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# Homework Help: Another quick integration q

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