- #1
rugapark
- 22
- 0
the question is [tex]\int 2x sec^2 (x^2) dx[/tex]
do i sub u= sec (x^2) ?
I so far have got to trying to sub u= sec(x^2) and getting du= 2 (sec x^2 tan x^2)... i have a strong feeling i fudged the "du" part. hmm.
do i sub u= sec (x^2) ?
I so far have got to trying to sub u= sec(x^2) and getting du= 2 (sec x^2 tan x^2)... i have a strong feeling i fudged the "du" part. hmm.