Answer: Solving Three Step Gas Cycle Homework Problem

  • Thread starter Thread starter xmonsterx
  • Start date Start date
  • Tags Tags
    Cycle Gas
AI Thread Summary
The discussion revolves around solving a three-step gas cycle problem involving a monatomic ideal gas. In the first step, the heat added to the gas during constant volume heating needs to be expressed in terms of pressure, volume, and a constant A. The second step requires calculating the work done by the gas during isothermal expansion, while the third step focuses on the work done during isobaric cooling. Participants express confusion over the calculations and seek clarification on how to properly account for initial and final states in their equations. The thread highlights the complexities of thermodynamic processes and the need for accurate application of relevant equations.
xmonsterx
Messages
11
Reaction score
0

Homework Statement


A monatomic ideal gas has pressure p_1 and temperature T_1. It is contained in a cylinder of volume V_1 with a movable piston, so that it can do work on the outside world.

Consider the following three-step transformation of the gas:

1. The gas is heated at constant volume until the pressure reaches Ap_1 (where A >1).
2. The gas is then expanded at constant temperature until the pressure returns to p_1.
3. The gas is then cooled at constant pressure until the volume has returned to V_1.

It may be helpful to sketch this process on the pV plane.

Part 1-
How much heat DeltaQ_1 is added to the gas during step 1 of the process?
Express the heat added in terms of p_1, V_1, and A.

Part 2-
How much work W_2 is done by the gas during step 2?
Express the work done in terms of p_1, V_1, and A.

Part 3-
How much work W_3 is done by the gas during step 3?
If you've drawn a graph of the process, you won't need to calculate an integral to answer this question.
Express the work done in terms of p_1, V_1, and A.

Homework Equations



R = 8.31

The Attempt at a Solution



Part 1-
I tried Q = p_1*V_1*(C_V/R) = 1.5*Ap_1*V_1 but I was told this is the final internal energy, not the change in internal energy. so I worked out that

Q = [1.5*p_1*V_1*(AT_1-T_1)] / T_1 but the answer does not depend on AT_1 or T_1

Part 2-
all I've got so far is
W = nRT*ln(V_f/V_i) = pV*ln(V_f/V_i)
but that's about as far as I get.

Part 3-
I got Ap_1*V_1 but this is what the value would be if it were coming from V = 0. So I re-arranged pV=nRT to eventually get

W = p_1[(p_1V_1)/(Ap_1) - V_1]
but this is also wrong how do I take into account the initial state, wouldn't I just be able to write W = (Ap_1V_1) - V_1 ?
 
Last edited:
Physics news on Phys.org
xmonsterx said:
Consider the following three-step transformation of the gas:

1. The gas is then expanded at constant temperature until the pressure returns to p_1.
2. The gas is then cooled at constant pressure until the volume has returned to V_1.

I think the first step isn't mentioned.
 
Gear300 said:
I think the first step isn't mentioned.

thanks for point that out! i fixed it! now its a three step cycle.

But i still don't know how to figure this problem out!


please help anyone! pleaseeeeeeeeee!
 
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top