Solving a 600 lb Suspended Load Problem

[benndamann33]

Hey guys,
I worked through this problem and feel as though I made a mistake. I attached the figure, without it it makes no sense.

Question: The suspended load weighs 600 lbs. Determine the reactions at A and B.

Examining just the bottom bar, I summed the forces in the x
and got Ax - BD cos(30) = 0
AX = BD cos(30)
and in the y direction
Ay +BD sin(30) -600 = 0
Ay = 600 - BDsin(30)

Moment balance around A
3BD sin(30) - 600*6 = 0
BD = 2400 lbs at 30 degrees to the -x axis
therefore
Ay = -600
Ax = 2078.5

I'd like to know if you guys agree with my answers and also...is the reaction at B equivalent to the force BD or is that incorrect? Thank you!
Ben
by the way - this isn't like a take home test I'm cheating on, it's a previous years test given to practice for this years test, not graded/collected or anything

 

[nilesh_pat]

. Just for practice.Your answers appear to be correct. The reaction at B is equivalent to the force BD, 2400 lbs at 30 degrees to the -x axis.

 

[piercas]

I would first commend you on your problem-solving skills and for seeking clarification on your approach. It is always important to double check and verify calculations, especially in a field as precise as engineering.

Based on the information provided, your approach and calculations seem correct. The reaction at B is equivalent to the force BD, as they are acting in the same direction. However, it is important to note that the reaction at B includes both the vertical and horizontal components, while BD only represents the horizontal component.

Additionally, I would suggest including units in your calculations to ensure accuracy and to make it easier for others to follow your work. Overall, it seems like you have a good understanding of the problem and have arrived at the correct solution. Keep up the good work!