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  1. Oct 14, 2006 #1
    Hey guys,
    I worked through this problem and feel as though I made a mistake. I attached the figure, without it it makes no sense.

    Question: The suspended load weighs 600 lbs. Determine the reactions at A and B.

    Examining just the bottom bar, I summed the forces in the x
    and got Ax - BD cos(30) = 0
    AX = BD cos(30)
    and in the y direction
    Ay +BD sin(30) -600 = 0
    Ay = 600 - BDsin(30)

    Moment balance around A
    3BD sin(30) - 600*6 = 0
    BD = 2400 lbs at 30 degrees to the -x axis
    Ay = -600
    Ax = 2078.5

    I'd like to know if you guys agree with my answers and also...is the reaction at B equivalent to the force BD or is that incorrect? Thank you!
    by the way - this isn't like a take home test I'm cheating on, it's a previous years test given to practice for this years test, not graded/collected or anything

    Attached Files:

  2. jcsd
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