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I worked through this problem and feel as though I made a mistake. I attached the figure, without it it makes no sense.

Question: The suspended load weighs 600 lbs. Determine the reactions at A and B.

Examining just the bottom bar, I summed the forces in the x

and got Ax - BD cos(30) = 0

AX = BD cos(30)

and in the y direction

Ay +BD sin(30) -600 = 0

Ay = 600 - BDsin(30)

Moment balance around A

3BD sin(30) - 600*6 = 0

BD = 2400 lbs at 30 degrees to the -x axis

therefore

Ay = -600

Ax = 2078.5

I'd like to know if you guys agree with my answers and also...is the reaction at B equivalent to the force BD or is that incorrect? Thank you!

Ben

by the way - this isn't like a take home test I'm cheating on, it's a previous years test given to practice for this years test, not graded/collected or anything

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# Homework Help: Answer verification

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