Antiderivative: natural logs, exponents

swooshfactory
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Homework Statement



I am trying to anti-differentiate (3t+2e^t)*[e^(-3t/2)]

Homework Equations





The Attempt at a Solution



I have simplified this into several forms, including [3t(e^(-3t/2)+2e^(-t/2)] . This form may or may not be accurate, but I am pretty sure that the form given at the beginning of this post is accurate. But I cannot anti-differentiate either of them. A u-substitution maybe? I'm not sure. I cannot move past the problem I need to solve until I complete this step. Any help would be appreciated. Thank you for looking.
 
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(3t+2e^t)e^{\frac{-3t}{2}}=3te^{\frac{-3t}{2}}+2e^{t+\frac{-3t}{2}}


Simplify this t+\frac{-3t}{2} part. Then use integration by parts on the te^{\frac{-3t}{2}} term.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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