AP Physics Multiple Choice Concept Question

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Adjusting the tension in a guitar string affects the speed of the traveling wave, which increases with higher tension. The frequency of the standing wave remains constant when the tension changes, as it is determined by the properties of the string and not the tension itself. Consequently, the wavelength will change in response to the speed increase while maintaining the same frequency. The correct answer to the question is A) 1 only, as only the speed of the wave changes with tension adjustments. Understanding these relationships is crucial for mastering wave mechanics in physics.
ShamTheCandle
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A standing wave pattern is created on a guitar string as a person tunes the guitar by changing the tension in the string. Which of the following properties of the waves on the string will change as a result of adjusting only the tension in the string?

1) Speed of the traveling wave that creates the pattern
2) Frequency of the standing wave
3) Wavelength of the standing wave

A) 1 only
B) 2 only
C) 1 and 2 only
D) 2 and 3 only
E) 1, 2 and 3
 
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Well what do you think?
 
diazona said:
Well what do you think?

I think that 1) is true, because as you increase Tension, velocity should increase since the formula v=(F/(m/L))^(1/2) for the standing waves. However, I don't know whether frequency increases or wavelength as a result, or both... I don't understand this concept very well.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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