Apparent magnitude of binary star?

AI Thread Summary
A binary star system has a total apparent magnitude of 15.00, with one star being twice as bright as the other. The apparent magnitude of the brighter star is calculated to be 15.44. The fainter star has an apparent magnitude of 4.50, leading to a discussion on how to determine the distance of the binary star system using the formula m-M=5log10(D/10pc). Participants highlight the importance of understanding the relationship between brightness ratios and apparent magnitudes. The conversation emphasizes the need to correctly apply these concepts to solve the problem effectively.
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[SOLVED] Apparent magnitude of binary star?

Homework Statement


A binary star has a total apparent magnitude of 15.00. One component star is twice as bright as the other.

a) Show that the apparent magnitude of the brighter star is 15.44.

b) The fainter star has an apparent magnitude of 4.50 . How far away is this binary star system? Express your answer in kiloparsencs.


Homework Equations



I think I should be using: m-M=5log10(D/10pc)

The Attempt at a Solution



I have done a little research and know that a binary star system is two or more stars orbitting a center of mass. I am not sure how I link this with the question. It says one component star is twie as bright as the other but is this apparent or absolule magnitude?
 
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You have to use the relationship between ratio of their brightness and apparent magnitudes.

b1/b2 = 2.512^(m2-m1).
 
Thankyou SO much. I have an exam tomorrow and this question seems to come up un all of the past papers but I just couldn't do it.

However I still can't do the question. if I put b1/b2=2 and then ssub in values and rearrange I get : m2-m1=-.7525.

Where do I go from here?
 
Last edited:
You also need m = -2.5 log ( b )
you know b1 in terms of b2, you know the total apparent mag
Rememebr brightnesses just add, but magnitudes don't!
 
samblue said:
Thankyou SO much. I have an exam tomorrow and this question seems to come up un all of the past papers but I just couldn't do it.

However I still can't do the question. if I put b1/b2=2 and then ssub in values and rearrange I get : m2-m1=-.7525.

Where do I go from here?

If the suffix 2 refers to the brighter star, then,

3/2 = 2.512^(m2 - 15). You get m2.
 
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