Application of Fourier series to pressure waves

Sam Harrison
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Homework Statement



Assume that a pressure wave produces a change in pressure at a point in space \Delta P(t) which is proportional to a sawtooth function of frequency f = 1/2 Hz.

(i) If the amplitude of the pressure wave is \Delta P_{0}, write down an expression for \Delta P(t).

(ii) Two oscillators, designed to respond to changes in pressure, resonate at a frequency f = 3/2 Hz and f = 5/4 Hz respectively. When the pressure wave encounters the oscillators, which of these will resonate and why?

Homework Equations



The Fourier expansion of a sawtooth function f(x) = x, -1 < x < 1 is given by

f(x) = \sum_{r=1}^{\infty} \frac{-2(-1)^{r}}{\pi r} \sin{\pi r x}

The Attempt at a Solution



Is the previous equation simply the answer to part (i) with the x's replaced with t's? Or is there a bit more to it? I think I'm missing something pretty obvious.

For part (ii), we know that r \pi t = 2 \pi ft and hence r = 2f. For f = 3/2 Hz, r = 3 and for f = 5/4 Hz, r = 5/2. Would only the first resonate as it is the only one that produces r that is an integer and hence satisfies the expansion above?
 
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Sam Harrison said:

Homework Statement



Assume that a pressure wave produces a change in pressure at a point in space \Delta P(t) which is proportional to a sawtooth function of frequency f = 1/2 Hz.

(i) If the amplitude of the pressure wave is \Delta P_{0}, write down an expression for \Delta P(t).

(ii) Two oscillators, designed to respond to changes in pressure, resonate at a frequency f = 3/2 Hz and f = 5/4 Hz respectively. When the pressure wave encounters the oscillators, which of these will resonate and why?

Homework Equations



The Fourier expansion of a sawtooth function f(x) = x, -1 < x < 1 is given by

f(x) = \sum_{r=1}^{\infty} \frac{-2(-1)^{r}}{\pi r} \sin{\pi r x}


The Attempt at a Solution



Is the previous equation simply the answer to part (i) with the x's replaced with t's? Or is there a bit more to it? I think I'm missing something pretty obvious.
You have to get the amplitude right as well.
For part (ii), we know that r \pi t = 2 \pi ft and hence r = 2f. For f = 3/2 Hz, r = 3 and for f = 5/4 Hz, r = 5/2. Would only the first resonate as it is the only one that produces r that is an integer and hence satisfies the expansion above?
Yes. The sawtooth pressure wave contains harmonics with frequencies equal to integral multiples of 1/2 Hz, so it has a 3/2-Hz component but lacks a 5/4-Hz component and will excite only the one resonator.
 
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