Applying Newton's Third Law of Mortion

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The discussion focuses on calculating the average force exerted on a ball that rebounds after falling from a height of 30 m and reaching a height of 20 m. Participants emphasize the importance of showing attempts at solving the problem to receive assistance. The concept of impulse and change in momentum is highlighted as a key approach to the solution. There is also clarification regarding the application of Newton's Third Law of Motion, specifically the action-reaction principle, and the need to consider the force the ball exerts on the ground. Overall, the conversation centers on understanding the physics involved in the scenario presented.
Rosieposy08
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Homework Statement



After falling from a rest from a height of 30 m, a .50 kg ball rebounds upward, reaching a height of 20 m. If the contact between ball and ground lasted 2.0 ms, what average force was exerted on the ball?

Homework Equations



2.0ms=.002s

The Attempt at a Solution

 
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Consider the total energy and direction (and change thereof) the ball has before and after the impact.
 
hello Rosieposy! Welcome to physics forums!

you need to show your attempt at solving the question, if you are stuck people here will help you.
 
Use impulse = change in momentum.
BTW how is this an application of Newton's Third Law of Motion. As I recall it was action reaction law. You are not considering the force exerted on the ground by the ball, are you?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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