Approaching Heat Transfer TNT Exercise Using Log-Log Plots

AI Thread Summary
The discussion focuses on solving a heat transfer problem using the formula f(y)=(ro*R^5/E*t^2) with given parameters. The user seeks guidance on how to approach part iv) of the exercise, specifically regarding the use of log-log plots. Suggestions include plotting R^5 against t^2 to determine the slope or taking the logarithm of both sides of the equation to plot log R versus log t, where the expected slope is 0.4. The user is encouraged to use a graphics package like Excel for analysis and to find the value of R at 1 second. The conversation emphasizes the effectiveness of the log-log approach for this problem.
williamcarter
Messages
153
Reaction score
4

Homework Statement


I would really appreciate if you could give me some hints regarding what exactly to do at iv)[/B]
iv)
gneill.JPG

gneill2.JPG


Given formulas:
formula.JPG

Homework Equations


f(y)=(ro*R^5/E*t^2)

The Attempt at a Solution


we know that f(y)=0.75
1ton TNT=4.184*10^9 J
ro=1.003kg/m^3

We have the above formula:f(y)=(ro*R^5/E*t^2)
we have almost everything, but I do not know exactly how to approach this problem and what exactly to do with that table.I was thinking of doing the slope,[/B]
 
Last edited:
Physics news on Phys.org
The image attachment is missing.
 
  • Like
Likes williamcarter
gneill said:
The image attachment is missing.
Ow,my bad, I will fix it, I don't know why it didn't upload maybe because format.
 
There are several possibilities:
1. Plot ##R^5## vs ##t^2## and determine the slope.

2. Take the log of both sides of the equation: ##5 \log R = \log \frac{Ef}{\rho}+2 \log t## or $$\log R = 0.2\log \frac{Ef}{\rho}+0.4 \log t$$
Use your graphics package (say Excel) to plot logR vs log t. The slope should be 0.4. Have your graphics package determine the equation of the best straight line. Find the value of R at 1 sec.

3. Calculate ##R^5/t^2## for all four data points, and take the average.

I would always choose item 2.
 
  • Like
Likes williamcarter
Chestermiller said:
There are several possibilities:
1. Plot ##R^5## vs ##t^2## and determine the slope.

2. Take the log of both sides of the equation: ##5 \log R = \log \frac{Ef}{\rho}+2 \log t## or $$\log R = 0.2\log \frac{Ef}{\rho}+0.4 \log t$$
Use your graphics package (say Excel) to plot logR vs log t. The slope should be 0.4. Have your graphics package determine the equation of the best straight line. Find the value of R at 1 sec.

3. Calculate ##R^5/t^2## for all four data points, and take the average.

I would always choose item 2.

Thank you, much appreciated !
 

Similar threads

Back
Top