Approaching Infinity: Solving Improper Integrals with Calc II Techniques

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Homework Statement


\int\frac{x}{(x^2+2)(x^2+2)} dx from 0 to infinity

Homework Equations


Improper integrals

The Attempt at a Solution


Lim_{t->\infty} \int\frac{t}{0} (\frac{x}{(x^2+2)(x^2+2)})

I tried integrating this by parts and also by partial fractions but neither seemed to lend itself nicely to the problem. (Choosing dv = (x^2+2)^(-2) made finding v ugly and based on the rules for choosing u shouldn't I choose x to be u?) And partial fractions didn't seem to work either. Any suggestions?
 
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That's a pretty ugly tex post but if you mean the integral of x*dx/(x^2+2) try u=x^2+2.
 
I am still trying to play with the formatting, sorry, I will write it out in words in the mean time: the integral of x over (x^2+2)^2 dx.

But, yes, it seems like that simple u-substitution will work! Thank you ... I feel so silly for overcomplicating the problem!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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