Arc length (mostly a problem with integration)

Geekchick
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Homework Statement



Find the arc length oh the graph f(x)=cosx on the integral [0,\frac{\pi}{2}]

Homework Equations



\int^{b}_{a}\sqrt{1+{f'(x)}^{2}}dx

The Attempt at a Solution



Alright so I took the derivative of f(x) to get f'(x)=-sinx then I squared it to get sin^{2}x so I could plug it into the formula to get \int^{\frac{\pi}{2}}_{0}\sqrt{1+sin^{2}x} the problem is when I try to integrate...well i can't. I tried to use substitution but since i don't have cos^{2}x anywhere I had some issues.
 
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Anybody? Please this is driving me crazy!
 
You can't do it. You have to do a numerical approximation
 
I get 1.910098938245763 with wxmaxima
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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