Are All Triplet States Symmetric in Spin Wavefunction Across Different Atoms?

Amith2006
Messages
416
Reaction score
2

Homework Statement



# The triplet state in helium atom is represented by a symmetric spin wavefunction. Are all triplet states of an atom represented by a symmetric spin wavefunction or is this just in the case of helium atom?

# Fermions are represented by an anti-symmetric total wavefunction. So if a pair of electrons is in the triplet state, it will be represented by a symmetric spin wavefunction and an anti-symmetric space wavefunction because,

Total wavefunction= \psi(space) x \psi(spin)

it is said that an anti-symmetric spatial wavefunction implies a greater distance between the electrons when compared to a symmetric spatial wave function as in the case of singlet state. Could anyone please help me in understanding the whole idea behind this?

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
Amith2006 said:
It is said that an anti-symmetric spatial wavefunction implies a greater distance between the electrons when compared to a symmetric spatial wave function as in the case of singlet state. Could anyone please help me in understanding the whole idea behind this?

Try plotting the spatial wavefunctions in the two cases, or find somewhere where they are already plotted.
The anti-symmetric spatial wavefunction means that there is a exp[r1-r2] appearing in the wavefunction instead of exp[-(r1+r2)] for electron 1 and 2. The wavefunction will then have minimal probability amplitude when r1 --> r2 so the electrons' expectation values are furthest from each other.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...

Similar threads

Back
Top