Are lost volts the difference between EMF and terminal potential difference?

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Homework Help Overview

The discussion revolves around the concept of "lost volts" in electrical circuits, specifically in relation to electromotive force (EMF) and terminal potential difference (pd). The context includes a potential divider circuit as an example.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definitions of "lost volts," EMF, and terminal pd, questioning how these terms relate to each other in practical scenarios. There is an inquiry into typical circuits that illustrate these concepts.

Discussion Status

The discussion is active, with participants seeking clarification on terminology and its implications in circuit analysis. Some have provided examples and definitions, while others are probing for deeper understanding of the concepts involved.

Contextual Notes

There is mention of regional variations in terminology, particularly between the UK and other regions, which may affect the understanding of "lost volts." The discussion also references specific values from a hypothetical scenario involving a cell's EMF and terminal pd.

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Are lost volts the difference between EMF and terminal pd?
 
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By "lost volts" I'm assuming you mean "voltage drop". Can you post a typical circuit that has generated this question?
 
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berkeman said:
By "lost volts" I'm assuming you mean "voltage drop". Can you post a typical circuit that has generated this question?
Actually its a general question, but the circuit used is say for example a potential divider
 
Okay, then what are "EMF" and "terminal pd" in the context of your question? The input battery voltage and the output of the 2-resistor voltage divider?
 
homeworkhelpls said:
Are lost volts the difference between EMF and terminal pd?
Maybe terminology varies regionally, but here in the UK that’s exactly what is meant by ‘lost volts’ for an electrical source.

E.g. a cell’s emf (measured open-circuit) is 1.60V. With some load, the p.d. between the cell’s terminals drops to 1.45V. Then the ‘lost volts’ = 1.60V - 1.45V = 0.15V.

The ‘lost volts’ value is often (especially for teaching and examination purposes here) taken to equal the product of the current through the supply and the supply’s notional internal resistance.
 
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