- #1
homeworkhelpls
- 41
- 1
- Homework Statement
- thats the statement
- Relevant Equations
- none
Are lost volts the difference between EMF and terminal pd?
Are lost volts the difference between EMF and terminal potential difference?
- Thread starter homeworkhelpls
- Start date
Click For Summary
Lost volts refer to the voltage drop that occurs in a circuit, specifically the difference between electromotive force (EMF) and terminal potential difference (pd). In a typical scenario, such as a voltage divider, the EMF is the open-circuit voltage of a battery, while the terminal pd is the voltage measured across the load. For example, if a cell has an EMF of 1.60V and the terminal pd drops to 1.45V under load, the lost volts would be 0.15V. This concept is often used in educational contexts to illustrate the relationship between current, internal resistance, and voltage drop. Understanding lost volts is crucial for analyzing circuit performance and efficiency.
My attempt:
Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE.
PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##.
PE of part in the tube = ##\frac{m}{l}(l - h)gh##.
Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##.
Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...