Are My Calculus Derivatives Correct?

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    Calculus Grade 12
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The discussion focuses on finding the derivatives of two functions. For the first function, y = x^5e^-3x, the original poster initially provided an incorrect derivative but later corrected it to y' = (5x^4 e^-3x) + (x^5 - 3e^-3x). The second function, y = (1 - e^-x) / (1 + e^2x), was also initially answered incorrectly, with feedback indicating that there were multiple errors. The poster is working on fixing the second question's derivative. Overall, the thread emphasizes the importance of careful differentiation and peer feedback in calculus.
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For both questions i have to find dy/dx
1. y=x^5e^-3x

I got (5x^4 e^-3x) + (x^5 (-3xe^-3x-1))

some how that doesn't look right to me. not too sure...

2.
1-e^-x
y= --------
1+e^2x
My answer was:


(e^-x) - (1-e^-x) (2xe^2x-1)
y'= -----------------------------
1+e^2x


Thanks for your help! It's much appreciated!
 
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eeyore81 said:
For both questions i have to find dy/dx
1. y=x^5e^-3x
I got (5x^4 e^-3x) + (x^5 (-3xe^-3x-1))
some how that doesn't look right to me. not too sure...
2.
1-e^-x
y= --------
1+e^2x
My answer was: (e^-x) - (1-e^-x) (2xe^2x-1)
y'= -----------------------------
1+e^2x
Thanks for your help! It's much appreciated!

1.It's wrong.It is an "x" too much.Figure out where. :wink:
2.It's wrong.Again an "x" too much,a 'minus' missing,a whole term missing and a sqare on the denominator.Figure it out yourself.

Daniel.
 
First of all, thanks for replying, I'm still working on fixing the 2nd question, but i think i got the first one, the answer should be:


y' = (5x^4 e^-3x) + (x^5 -3e^-3x)
 
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