amcavoy
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For the molecule \textrm{Ni}\left(\textrm{OH}\right)_{2}\textrm{Cl}\left(\textrm{NH}_{3}\right)_{3}, how do you determine the number of geometric and optical isomers? I first drew the molecule with a central \textrm{Cl} bonded to three \textrm{NH}_{3} molecules and a \textrm{Ni}; the \textrm{Ni} was in turn bonded to two \textrm{OH} molecules. From this, it appeared that no matter how I moved the atoms surrounding the central atom, the configuration would always be the same; it would just be rotated counterclockwise or clockwise.